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\begin{document}
\title{Prorosity-Based Methods for Solving Stochastic Feasibility Problems}
\author{Kay Barshad\thanks{Department of Mathematics, The Technion -- Israel Institute of Technology,
32000 Haifa, Israel\protect \\
 \Letter ~ \protect\href{mailto:kaybarshad\%40technion.ac.il}{kaybarshad@technion.ac.il}}\and Simeon Reich\thanks{Department of Mathematics, The Technion -- Israel Institute of Technology,
32000 Haifa, Israel\protect \\
 \Letter ~ \protect\href{mailto:sreich\%40technion.ac.il}{sreich@technion.ac.il}}\and Alexander J. Zaslavski\thanks{Department of Mathematics, The Technion -- Israel Institute of Technology,
32000 Haifa, Israel\protect \\
 \Letter ~ \protect\href{mailto:ajzasl\%40technion.ac.il}{ajzasl@technion.ac.il}}}
\maketitle
\begin{abstract}
\noindent The notion of porosity is well known in Optimization and
Nonlinear Analysis. Its importance is brought out by the fact that
the complement of a $\sigma$-porous subset of a complete pseudo-metric
space is a residual set, while the existence of the latter is essential
in many problems which apply the generic approach. Thus, under certain
circumstances, some refinements of known results can be achieved by
looking for porous sets. In 2001 Gabour, Reich and Zaslavski developed
certain generic methods for solving stochastic feasibility problems.
This topic was further investigated in 2021 by Barshad, Reich and
Zaslavski, who provided more general results in the case of unbounded
sets. In the present paper we introduce and examine new generic methods
that deal with the aforesaid problems, in which, in contrast with
previous studies, we consider sigma-porous sets instead of meager
ones.

\noindent \textbf{2010 Mathematics Subject Classification: }37B25,
46N10, 47J25, 54E50, 54E52, 90C30, 90C48.

\noindent \textbf{Keywords and phrases:} Baire category, Banach space,
common fixed point problem, generic convergence, porous set, residual
set, stochastic feasibility problem.
\end{abstract}

\section{\label{sec:Background}Introduction and background}

We consider (generalized) stochastic feasibility problems from the
point of view of the generic approach (for more applications of this
approach, see, for example, \cite{key-6}). These are the problems
of finding almost common fixed points of measurable (with respect
to a probability measure) families of mappings. Namely, we provide
generic methods for finding almost common fixed points by using the
notion of porosity. Our results are applicable to both the consistent
case (that is, the case where the aforesaid almost common fixed points
exist) and the inconsistent case (that is, the case where there are
no common fixed points at all).

We begin by recalling the definitions of porosity and local convexity.

Given a pseudo-metric space $\left(Y,\rho\right)$, we denote by $B_{\rho}\left(y,r\right)$,
for each $y\in Y$ and $r>0$, the open ball in $\left(Y,\rho\right)$
of center $y$ and radius $r$. Recall that a subset $E$ of a complete
pseudo-metric space $\left(Y,\rho\right)$ is called a \textit{porous}
subset of $Y$ if there exist $\alpha\in\left(0,1\right)$ and $r_{0}>0$
such that for each $r\in\left(0,r_{0}\right]$ and each $y\in Y$,
there exists a point $z\in Y$ for which
\[
B_{\rho}\left(z,\alpha r\right)\subset B_{\rho}\left(y,r\right)\backslash E.
\]
A subset of $Y$ is called a \textit{$\sigma$-porous }subset of $Y$
if it is a countable union of porous subsets of $Y$. Note that since
a porous set is nowhere dense, any $\sigma$-porous set is of the
first category and hence its complement is residual in $\left(Y,\rho\right)$,
that is, it contains a countable intersection of open and dense subsets
of $\left(Y,\rho\right)$. For this reason, there is a considerable
interest in $\sigma$-porous sets while searching for generic solutions
to optimization problems. More information concerning the notion of
porosity and its applications can be found, for example, in \cite{key-1},
\cite{key-2}, \cite{key-6} and \cite{key-3}.

Recall that a topological vector space $V$ with the topology $T$
is said to be a \textit{locally convex space} if there exists a family
$\mathscr{P}$ of pseudo-norms on $V$ such that the family of open
balls $\left\{ B_{\rho}\left(x_{0},\varepsilon\right):x_{0}\in V,\varepsilon>0,\rho\in\mathscr{P}\right\} $
is a subbasis for $T$ and $\cap_{\rho\in\mathscr{P}}Z_{\rho}=\left\{ 0\right\} $,
where $Z_{\rho}=\left\{ x\in V:\rho\left(x\right)=0\right\} $ for
each $\rho\in\mathscr{P}$. Clearly, every normed space (as a topological
vector space with respect to its norm) is a locally convex space.
In the sequel we use the following result (see Theorem 3.9 in \cite{key-10}).
\begin{thm}
\label{Theorem 3.9 in Conway} Let $V$ be a real locally convex topological
vector space, and let $A$ and B be two disjoint closed and convex
subsets of $V$. If either $A$ or $B$ is compact, then $A$ and
$B$ are strictly separated, that is, there is $\alpha\in\mathbb{R}$
and a continuous linear functional $\phi:V\rightarrow\mathbb{R}$
such that $\phi\left(a\right)>\alpha$ for each $a\in A$ and $\phi\left(b\right)<\alpha$
for each $b\in B$.
\end{thm}
Now we introduce the spaces for which we investigate the stochastic
feasibility problem. Other spaces which can be considered regarding
this problem, can be found, for example, in \cite{key-4} and \cite{key-11}.

Suppose that $\left(X,\left\Vert \cdot\right\Vert \right)$ is a normed
vector space with norm $\left\Vert \cdot\right\Vert $, $F$ is a
nonempty, closed, convex and bounded subset of $X$, $\left(\Omega,\mathcal{A},\mu\right)$
is a probability measure space (more information on measure spaces
and measurable mappings can be found, for example, in \cite{key-1})
and $K$ is a subset of $X$ which contains $F$. Denote by $\mathcal{N}$
the set of all nonexpansive mappings $A:K\rightarrow F$, that is,
all mappings $A:K\rightarrow F$ such that $\left\Vert Ax-Ay\right\Vert \le\left\Vert x-y\right\Vert $
for each $x,y\in K$. For the set $\mathcal{N}$, define a metric
$\rho_{\mathcal{N}}:\mathcal{N}\times\mathcal{N}\rightarrow\mathbb{R}$
by
\[
\rho_{\mathcal{N}}\left(A,B\right):=\sup\left\{ \left\Vert Ax-Bx\right\Vert :\,x\in K\right\} ,\,A,B\in\mathcal{N}.
\]
Clearly, the metric space $\left(\mathcal{N},\rho_{\mathcal{N}}\right)$
is complete if $\left(X,\left\Vert \cdot\right\Vert \right)$ is a
Banach space.

Denote by $\mathcal{N}_{\Omega}$ the set of all mappings $T:\Omega\rightarrow\mathcal{N}$
such that for each $x\in K$, the mapping $T_{x}^{\prime}:\Omega\rightarrow F$,
defined, for each $\omega\in\Omega$, by $T_{x}^{\prime}\left(\omega\right):=T\left(\omega\right)\left(x\right)$,
is measurable. It is not difficult to see that if $T\in\mathcal{N}_{\Omega}$,
then $T_{x}^{\prime}$ is integrable on $\Omega$. For each $T\in\mathcal{N}_{\Omega}$,
define an operator $\widetilde{T}:K\rightarrow F$ by $\widetilde{T}x=\int_{\Omega}T_{x}^{\prime}\left(\omega\right)d\mu\left(\omega\right)$
for each $x\in K$. By Theorem \ref{Theorem 3.9 in Conway}, this
is indeed a mapping the image of which is contained in $F$. Note
that the mapping defined on $\mathcal{N}_{\Omega}$ by $T\mapsto\widetilde{T}$
is onto $\mathcal{N}$. Clearly, for each $T\in\mathcal{N}_{\Omega}$,
we have $\widetilde{T}\in\mathcal{N}$. Thus we consider the topology
defined by the following pseudo-metric on $\mathcal{N}_{\Omega}$:
\[
\rho_{\mathcal{N}_{\Omega}}\left(T,S\right):=\rho_{\mathcal{N}}\left(\widetilde{T},\widetilde{S}\right),\,T,S\in\mathcal{N}_{\Omega}.
\]
It is not difficult to see that the pseudo-metric space $\left(\mathcal{N}_{\Omega},\rho_{\mathcal{N}_{\Omega}}\right)$
is complete if $\left(X,\left\Vert \cdot\right\Vert \right)$ is a
Banach space.

Denote by $\mathcal{M}_{\Omega}$ the set of all sequences $\left\{ T_{n}\right\} _{n=1}^{\infty}\subset\mathcal{N}_{\Omega}$.
We define a pseudo-metric $\rho_{\mathcal{M}_{\Omega}}:\mathcal{M}_{\Omega}\times\mathcal{M}_{\Omega}\rightarrow\mathbb{R}$
on $\mathcal{N}_{\Omega}$ in the following way:
\[
\rho_{\mathcal{M}_{\Omega}}\left(\left\{ T_{n}\right\} _{n=1}^{\infty},\left\{ S_{n}\right\} _{n=1}^{\infty}\right):=\sup\left\{ \rho_{\mathcal{N}_{\Omega}}\left(T_{n},S_{n}\right):\,n=1,2\dots\right\} ,\,\left\{ T_{n}\right\} _{n=1}^{\infty},\left\{ S_{n}\right\} _{n=1}^{\infty}\in\mathcal{M}_{\Omega}.
\]
Obviously, this space is complete if $\left(X,\left\Vert \cdot\right\Vert \right)$
is a Banach space.

The rest of the paper is organized as follows. In Section \ref{sec2}
we state our main results. Two auxiliary assertions are presented
in Section \ref{sec3}. In Section \ref{sec4} we provide the proofs
of our main results.

In all our results we also assume that $\left(X,\left\Vert \cdot\right\Vert \right)$
is a Banach space.

\section{\label{sec2}Statements of the main results}

In this section we state our main results. We establish them in Section
\ref{sec4} below.

Recall that for each $T\in\mathcal{\mathcal{N}}_{\Omega}$, a point
$x\in K$ is an \textit{almost common fixed point} of the family $\left\{ T\left(\omega\right)\right\} _{\omega\in\Omega}$
if $T\left(\omega\right)x=x$ for almost all $\omega\in\Omega$. Similarly,
for each sequence $\left\{ T_{n}\right\} _{n=1}^{\infty}\in\mathcal{\mathcal{M}}_{\Omega}$,
a point $x\in K$ is an \textit{almost common fixed point} of the
family $\left\{ T_{n}\left(\omega\right)\right\} _{\omega\in\Omega,\,n=1,2\dots}$
if $T_{n}\left(\omega\right)x=x$ for all $n=1,2,\dots$ and almost
all $\omega\in\Omega$.
\begin{thm}
\label{Theorem 1}There exists a set $\mathcal{F\subset}\mathcal{M}_{\Omega}$
such that $\mathcal{M}_{\Omega}\backslash\mathcal{F}$ is a $\sigma$-porous
subset of $\mathcal{M}_{\Omega}$ and for each $\left\{ T_{n}\right\} _{n=1}^{\infty}\in\mathcal{F}$,
the following assertion holds true:

For each $\varepsilon>0$, there is a positive integer $N$ such that
for each integer $n\ge N$ and each mapping $s:\left\{ 1,2,\dots\right\} \rightarrow\left\{ 1,2,\dots\right\} $,
we have
\[
\left\Vert \widetilde{T_{s\left(n\right)}}\dots\widetilde{T_{s\left(1\right)}}x-\widetilde{T_{s\left(n\right)}}\dots\widetilde{T_{s\left(1\right)}}y\right\Vert <\varepsilon
\]
for each $x,y\in K$. Consequently, if there is an almost common fixed
point of the family $\left\{ T_{n}\left(\omega\right)\right\} _{\omega\in\Omega,\,n=1,2\dots}$,
then it is unique and for each $x\in K$, the sequence $\left\{ \widetilde{T_{s\left(n\right)}}\dots\widetilde{T_{s\left(1\right)}}x\right\} _{n=1}^{\infty}$
converges to it as $n\rightarrow\infty$, uniformly on $K$, for each
mapping $s:\left\{ 1,2,\dots\right\} \rightarrow\left\{ 1,2,\dots\right\} $.
\end{thm}
%
\begin{thm}
\label{Theorem 2} There exists a set $\mathcal{F\subset}\mathcal{N}_{\Omega}$
such that the set $\mathcal{G}:=\mathcal{N}_{\Omega}\backslash\mathcal{F}$
a $\sigma$-porous subset of $\mathcal{N}_{\Omega},$ and for each
$T\in\mathcal{F}$, the following assertion holds true:

There exists $x_{T}\in K$ which is the unique fixed point of the
operator $\widetilde{T}$ such that for each $x\in K$, the sequence
$\left\{ \widetilde{T}^{n}x\right\} _{n=1}^{\infty}$ converges to
$x_{T}$ as $n\rightarrow\infty$, uniformly on $K$. Moreover, the
set $\mathfrak{F}$ of all almost common fixed points of the family
$\left\{ T\left(\omega\right)\right\} _{\omega\in\Omega}$ is contained
in $\left\{ x_{T}\right\} $. As a result, if $\mathfrak{F}\not=\emptyset$,
then $x_{T}$ is the unique almost common fixed point of the family
$\left\{ T\left(\omega\right)\right\} _{\omega\in\Omega}$.
\end{thm}

\section{\label{sec3}Auxiliary results}

In this section we present two lemmata which will be used in the proofs
of our main results. We start by defining three sequences which we
use in the proofs of these lemmata.

Choose $z_{0}\in F$ and set $r_{0}=1$. We first define the sequence
$\left\{ \alpha_{k}\right\} _{k=1}^{\infty}$ of positive numbers
by
\begin{equation}
\alpha_{k}=2^{-1}\left(1+2k\left(2\sup_{z\in F}\left\Vert z\right\Vert +1\right)\right)^{-1}\in\left(0,1\right).\label{eq:-4}
\end{equation}
Clearly, for each positive integer $k$,
\begin{equation}
\left(1-\alpha_{k}\right)\left(2\sup_{z\in F}\left\Vert z\right\Vert +1\right)^{-1}\in\left(0,1\right)\label{eq:-30}
\end{equation}
and
\begin{equation}
\left(1-\alpha_{k}\right)\left(2\sup_{z\in F}\left\Vert z\right\Vert +1\right)^{-1}-2\alpha_{k}k=2^{-1}\left(2\sup_{z\in F}\left\Vert z\right\Vert +1\right)^{-1}>0.\label{eq:-31}
\end{equation}
Using \eqref{eq:-31}, for each $r\in\left(0,r_{0}\right]$, we choose
sequences $\left\{ \gamma_{k}^{r}\right\} _{k=1}^{\infty}$ and $\left\{ N_{k}^{r}\right\} _{k=1}^{\infty}$
of positive numbers such that
\begin{equation}
\gamma_{k}^{r}\in\left(2\alpha_{k}kr,\left(1-\alpha_{k}\right)r\left(2\sup_{z\in F}\left\Vert z\right\Vert +1\right)^{-1}\right)\label{eq:-29}
\end{equation}
and
\begin{equation}
N_{k}^{r}>2\left(\gamma_{k}^{r}k^{-1}-2\alpha_{k}r\right)^{-1}\sup_{z\in F}\left\Vert z\right\Vert +1\label{eq:-26}
\end{equation}
for each positive integer $k$. Evidently, by\eqref{eq:-4}, \eqref{eq:-30}
and \eqref{eq:-29}, $\gamma_{k}^{r}\in\left(0,1\right)$.
\begin{lem}
\label{lem1}Assume that $k$ is a positive integer and let $\mathcal{F}_{k}$
be the set of all sequences $\left\{ T_{n}\right\} _{n=1}^{\infty}\in\mathcal{M}_{\Omega}$
for which there exists a positive integer $N$ such that for each
mapping $s:\left\{ 1,2,\dots\right\} \rightarrow\left\{ 1,2,\dots\right\} $,
we have

\[
\left\Vert \widetilde{T_{s\left(N\right)}}\dots\widetilde{T_{s\left(1\right)}}x-\widetilde{T_{s\left(N\right)}}\dots\widetilde{T_{s\left(1\right)}}y\right\Vert <k^{-1}
\]
for each $x,y\in K$. Then the set $\mathcal{G}_{k}:=\mathcal{M}_{\Omega}\backslash\mathcal{F}_{k}$
is a porous subset of $\mathcal{M}_{\Omega}$.
\end{lem}
\begin{proof}
Assume that $\left\{ T_{n}\right\} _{n=1}^{\infty}\in\mathcal{M}_{\Omega}$
and $r\in\left(0,r_{0}\right]$. Define a sequence of mappings $\left\{ T_{n}^{\gamma_{k}^{r}}\right\} _{n=1}^{\infty}$,
$T_{n}^{\gamma_{k}^{r}}:\Omega\rightarrow\mathcal{N}$, by
\[
T_{n}^{\gamma_{k}^{r}}\left(\omega\right)x:=\left(1-\gamma_{k}^{r}\right)T_{n}\left(\omega\right)x+\gamma_{k}^{r}z_{0},\,n=1,2,\dots
\]
for each $\omega\in\Omega$ and each $x\in K$. Clearly, $\left\{ T_{n}^{\gamma_{k}^{r}}\right\} _{n=1}^{\infty}\in\mathcal{M}_{\Omega}$
and for each $n=1,2,\dots$,
\begin{gather*}
\widetilde{T_{n}^{\gamma_{k}^{r}}}x=\int_{\Omega}\left(\left(1-\gamma_{k}^{r}\right)T_{n}\left(\omega\right)x+\gamma_{k}^{r}z_{0}\right)d\mu\left(\omega\right)=\gamma_{k}^{r}z_{0}+\left(1-\gamma_{k}^{r}\right)\int_{\Omega}T_{n}\left(\omega\right)xd\mu\left(\omega\right)\\
=\left(1-\gamma_{k}^{r}\right)\widetilde{T_{n}}x+\gamma_{k}^{r}z_{0}
\end{gather*}
for each $x\in K$. We have
\begin{equation}
\rho_{\mathcal{M}_{\Omega}}\left(\left\{ T_{n}^{\gamma_{k}^{r}}\right\} _{n=1}^{\infty},\left\{ T_{n}\right\} _{n=1}^{\infty}\right)\le2\gamma_{k}^{r}\sup_{z\in F}\left\Vert z\right\Vert ,\label{eq:-1}
\end{equation}
as well as, for each positive integer $n$,
\begin{equation}
\left\Vert \widetilde{T_{n}^{\gamma_{k}^{r}}}x-\widetilde{T_{n}^{\gamma_{k}^{r}}}y\right\Vert \le\left(1-\gamma_{k}^{r}\right)\left\Vert x-y\right\Vert \label{eq:-2}
\end{equation}
for each $x,y\in K$.

Let $\left\{ S_{n}\right\} _{n=1}^{\infty}\in\mathcal{M}_{\Omega}$
satisfy
\begin{equation}
\rho_{\mathcal{M}_{\Omega}}\left(\left\{ T_{n}^{\gamma_{k}^{r}}\right\} _{n=1}^{\infty},\left\{ S_{n}\right\} _{n=1}^{\infty}\right)<\alpha_{k}r.\label{eq:-13}
\end{equation}
Assume that $s:\left\{ 1,2,\dots\right\} \rightarrow\left\{ 1,2,\dots\right\} $
is an arbitrary mapping. We claim that
\begin{equation}
\left\Vert \widetilde{S_{s\left(N_{k}^{r}\right)}}\dots\widetilde{S_{s\left(1\right)}}x-\widetilde{S_{s\left(N_{k}^{r}\right)}}\dots\widetilde{S_{s\left(1\right)}}y\right\Vert <k^{-1}\label{eq:-27}
\end{equation}
for each $x,y\in K$. Suppose to the contrary that this does not hold.
Then there exist points $x_{0},y_{0}\in K$ such that for each $i=0\dots N_{k}^{r}$,
we have

\begin{equation}
\left\Vert \widetilde{S_{s\left(i\right)}}\dots\widetilde{S_{s\left(1\right)}}x_{0}-\widetilde{S_{s\left(i\right)}}\dots\widetilde{S_{s\left(1\right)}}y_{0}\right\Vert \ge k^{-1}.\label{eq:-25}
\end{equation}
Using the triangle inequality, \eqref{eq:-13}, \eqref{eq:-2} and
\eqref{eq:-25}, we obtain that for each $i=1\dots N_{k}^{r}$,
\begin{gather*}
\left\Vert \widetilde{S_{s\left(i\right)}}\dots\widetilde{S_{s\left(1\right)}}x_{0}-\widetilde{S_{s\left(i\right)}}\dots\widetilde{S_{s\left(1\right)}}y_{0}\right\Vert \le\\
\left\Vert \widetilde{S_{s\left(i\right)}}\widetilde{S_{s\left(i-1\right)}}\dots\widetilde{S_{s\left(1\right)}}x_{0}-\widetilde{T_{s\left(i\right)}^{\gamma_{k}^{r}}}\widetilde{S_{s\left(i-1\right)}}\dots\widetilde{S_{s(1}}x_{0}\right\Vert +\\
\left\Vert \widetilde{T_{s\left(i\right)}^{\gamma_{k}^{r}}}\widetilde{S_{s\left(i-1\right)}}\dots\widetilde{S_{s\left(1\right)}}x_{0}-\widetilde{T_{s\left(i\right)}^{\gamma_{k}^{r}}}\widetilde{S_{s\left(i-1\right)}}\dots\widetilde{S_{s\left(1\right)}}y_{0}\right\Vert +\\
\left\Vert \widetilde{T_{s\left(i\right)}^{\gamma_{k}^{r}}}\widetilde{S_{s\left(i-1\right)}}\dots\widetilde{S_{s\left(1\right)}}y_{0}-\widetilde{S_{s\left(i\right)}}\dots\widetilde{S_{s\left(1\right)}}y_{0}\right\Vert <\\
2\alpha_{k}r+\left(1-\gamma_{k}^{r}\right)\left\Vert \widetilde{S_{s\left(i-1\right)}}\dots\widetilde{S_{s\left(1\right)}}x_{0}-\widetilde{S_{s\left(i-1\right)}}\dots\widetilde{S_{s\left(1\right)}}y_{0}\right\Vert \\
\le\left\Vert \widetilde{S_{s\left(i-1\right)}}\dots\widetilde{S_{s\left(1\right)}}x_{0}-\widetilde{S_{s\left(i-1\right)}}\dots\widetilde{S_{s\left(1\right)}}y_{0}\right\Vert +\\
2\alpha_{k}r-\gamma_{k}^{r}k^{-1}.
\end{gather*}
Hence by \eqref{eq:-29}, we have
\begin{gather*}
\left\Vert \widetilde{S_{s\left(i-1\right)}}\dots\widetilde{S_{s\left(1\right)}}x_{0}-\widetilde{S_{s\left(i-1\right)}}\dots\widetilde{S_{s\left(1\right)}}y_{0}\right\Vert -\left\Vert \widetilde{S_{s\left(i\right)}}\dots\widetilde{S_{s\left(1\right)}}x_{0}-\widetilde{S_{s\left(i\right)}}\dots\widetilde{S_{s\left(1\right)}}y_{0}\right\Vert \\
>\gamma_{k}^{r}k^{-1}-2\alpha_{k}r>0
\end{gather*}
for each $i=1\dots N_{k}^{r}$. Therefore
\begin{gather*}
2\sup_{z\in F}\left\Vert z\right\Vert \ge\left\Vert \widetilde{S_{s\left(1\right)}}x_{0}-\widetilde{S_{s\left(1\right)}}y_{0}\right\Vert -\left\Vert \widetilde{S_{s\left(N_{k}^{r}\right)}}\dots\widetilde{S_{s\left(1\right)}}x_{0}-\widetilde{S_{s\left(N_{k}^{r}\right)}}\dots\widetilde{S_{s\left(1\right)}}y_{0}\right\Vert =\\
\Sigma_{i=2}^{N_{k}^{r}}\left(\left\Vert \widetilde{S_{s\left(i-1\right)}}\dots\widetilde{S_{s\left(1\right)}}x_{0}-\widetilde{S_{s\left(i-1\right)}}\dots\widetilde{S_{s\left(1\right)}}y_{0}\right\Vert -\left\Vert \widetilde{S_{s\left(i\right)}}\dots\widetilde{S_{s\left(1\right)}}x_{0}-\widetilde{S_{s\left(i\right)}}\dots\widetilde{S_{s\left(1\right)}}y_{0}\right\Vert \right)\\
>\left(N_{k}^{r}-1\right)\left(\gamma_{k}^{r}k^{-1}-2\alpha_{k}r\right).
\end{gather*}
As a result,
\[
N_{k}^{r}<2\left(\gamma_{k}^{r}k^{-1}-2\alpha_{k}r\right)^{-1}\sup_{z\in F}\left\Vert z\right\Vert +1.
\]
This, however, contradicts \eqref{eq:-26}. Thus \eqref{eq:-27} does
hold. Next, using the triangle inequality, we see by \eqref{eq:-1},
\eqref{eq:-13} and \eqref{eq:-29} that
\begin{gather}
\rho_{\mathcal{M}_{\Omega}}\left(\left\{ T_{n}\right\} _{n=1}^{\infty},\left\{ S_{n}\right\} _{n=1}^{\infty}\right)\le\rho_{\mathcal{M}_{\Omega}}\left(\left\{ T_{n}\right\} _{n=1}^{\infty},\left\{ T_{n}^{\gamma_{k}^{r}}\right\} _{n=1}^{\infty}\right)+\rho_{\mathcal{M}_{\Omega}}\left(\left\{ T_{n}^{\gamma_{k}^{r}}\right\} _{n=1}^{\infty},\left\{ S_{n}\right\} _{n=1}^{\infty}\right)<\nonumber \\
2\gamma_{k}^{r}\sup_{z\in F}\left\Vert z\right\Vert +\alpha_{k}r<\left(1-\alpha_{k}\right)r+\alpha_{k}r=r.\label{eq:-32}
\end{gather}
From \eqref{eq:-27} and \eqref{eq:-32} it now follows that
\[
B_{\rho_{\mathcal{M}_{\Omega}}}\left(\left\{ T_{n}^{\gamma_{k}^{r}}\right\} _{n=1}^{\infty},\alpha_{k}r\right)\subset B_{\rho_{\mathcal{M}_{\Omega}}}\left(\left\{ T_{n}\right\} _{n=1}^{\infty},r\right)\cap\mathcal{F}_{k}=B_{\rho_{\mathcal{M}_{\Omega}}}\left(\left\{ T_{n}\right\} _{n=1}^{\infty},r\right)\backslash\mathcal{G}_{k}.
\]
Hence $\mathcal{G}_{k}$ is indeed a porous subset of $\mathcal{M}_{\Omega}$,
as asserted.
\end{proof}
\begin{lem}
\label{lem2}Assume that $k$ is a positive integer and let $\mathcal{F}_{k}$
be the set of all mappings $T\in\mathcal{N}_{\Omega}$ for which there
exists a positive integer $N$ such that
\[
\left\Vert \widetilde{T}^{N}x-\widetilde{T}^{N}y\right\Vert <k^{-1}
\]
for each $x,y\in K$. Then the set $\mathcal{G}_{k}:=\mathcal{N}_{\Omega}\backslash\mathcal{F}_{k}$
is a porous subset of $\mathcal{N}_{\Omega}$.
\end{lem}
\begin{proof}
Assume that $T\in\mathcal{N}_{\Omega}$ and $r\in\left(0,r_{0}\right]$.
Define a mapping $T_{\gamma_{k}^{r}}$, $T_{\gamma_{k}^{r}}:\Omega\rightarrow\mathcal{N}$,
by
\[
T_{\gamma_{k}^{r}}\left(\omega\right)x:=\left(1-\gamma_{k}^{r}\right)T\left(\omega\right)x+\gamma_{k}^{r}z_{0}
\]
for each $\omega\in\Omega$ and each $x\in K$. Clearly, $T_{\gamma_{k}^{r}}\in\mathcal{N}_{\Omega}$
and
\begin{gather*}
\widetilde{T_{\gamma_{k}^{r}}}x=\int_{\Omega}\left(\left(1-\gamma_{k}^{r}\right)T\left(\omega\right)x+\gamma_{k}^{r}z_{0}\right)d\mu\left(\omega\right)=\gamma_{k}^{r}z_{0}+\left(1-\gamma_{k}^{r}\right)\int_{\Omega}T\left(\omega\right)xd\mu\left(\omega\right)\\
=\left(1-\gamma_{k}^{r}\right)\widetilde{T}x+\gamma_{k}^{r}z_{0}
\end{gather*}
for each $x\in K$. We have
\begin{equation}
\rho_{\mathcal{N}_{\Omega}}\left(T_{\gamma_{k}^{r}},T\right)\le2\gamma_{k}^{r}\sup_{z\in F}\left\Vert z\right\Vert ,\label{eq:-1-1}
\end{equation}
as well as
\begin{equation}
\left\Vert \widetilde{T_{\gamma_{k}^{r}}}x-\widetilde{T_{\gamma_{k}^{r}}}y\right\Vert \le\left(1-\gamma_{k}^{r}\right)\left\Vert x-y\right\Vert \label{eq:-2-1}
\end{equation}
for each $x,y\in K$.

Let $S\in\mathcal{N}_{\Omega}$ satisfy
\begin{equation}
\rho_{\mathcal{N}_{\Omega}}\left(T_{\gamma_{k}^{r}},S\right)<\alpha_{k}r.\label{eq:-13-1}
\end{equation}
We claim that
\begin{equation}
\left\Vert \widetilde{S}^{N_{k}^{r}}x-\widetilde{S}^{N_{k}^{r}}y\right\Vert <k^{-1}\label{eq:-27-1}
\end{equation}
for each $x,y\in K$. Suppose to the contrary that this does not hold.
Then there exist points $x_{0},y_{0}\in K$ such that for each $i=0\dots N_{k}^{r}$,
we have

\begin{equation}
\left\Vert \widetilde{S}^{i}x_{0}-\widetilde{S}^{i}y_{0}\right\Vert \ge k^{-1}.\label{eq:-25-1}
\end{equation}
Using the triangle inequality, \eqref{eq:-13-1}, \eqref{eq:-2-1}
and \eqref{eq:-25-1}, we see that for each $i=1\dots N_{k}^{r}$,
\begin{gather*}
\left\Vert \widetilde{S}^{i}x_{0}-\widetilde{S}^{i}y_{0}\right\Vert \le\left\Vert \widetilde{S}\widetilde{S}^{i-1}x_{0}-\widetilde{T_{\gamma_{k}^{r}}}\widetilde{S}^{i-1}x_{0}\right\Vert +\\
\left\Vert \widetilde{T_{\gamma_{k}^{r}}}\widetilde{S}^{i-1}x_{0}-\widetilde{T_{\gamma_{k}^{r}}}\widetilde{S}^{i-1}y_{0}\right\Vert +\left\Vert \widetilde{T_{\gamma_{k}^{r}}}\widetilde{S}^{i-1}y_{0}-\widetilde{S}\widetilde{S}^{i-1}y_{0}\right\Vert <\\
2\alpha_{k}r+\left(1-\gamma_{k}^{r}\right)\left\Vert \widetilde{S}^{i-1}x_{0}-\widetilde{S}^{i-1}y_{0}\right\Vert \\
\le\left\Vert \widetilde{S}^{i-1}x_{0}-\widetilde{S}^{i-1}y_{0}\right\Vert +\\
2\alpha_{k}r-\gamma_{k}^{r}k^{-1}.
\end{gather*}
Hence by \eqref{eq:-29},
\begin{gather*}
\left\Vert \widetilde{S}^{i-1}x_{0}-\widetilde{S}^{i-1}y_{0}\right\Vert -\left\Vert \widetilde{S}^{i}x_{0}-\widetilde{S}^{i}y_{0}\right\Vert \\
>\gamma_{k}^{r}k^{-1}-2\alpha_{k}r>0
\end{gather*}
for each $i=1\dots N_{k}^{r}$. Therefore
\begin{gather*}
2\sup_{z\in F}\left\Vert z\right\Vert \ge\left\Vert \widetilde{S}x_{0}-\widetilde{S}y_{0}\right\Vert -\left\Vert \widetilde{S}^{N_{k}^{r}}x_{0}-\widetilde{S}^{N_{k}^{r}}y_{0}\right\Vert =\\
\Sigma_{i=2}^{N_{k}^{r}}\left(\left\Vert \widetilde{S}^{i-1}x_{0}-\widetilde{S}^{i-1}y_{0}\right\Vert -\left\Vert \widetilde{S}^{i}x_{0}-\widetilde{S}^{i}y_{0}\right\Vert \right)\\
>\left(N_{k}^{r}-1\right)\left(\gamma_{k}^{r}k^{-1}-2\alpha_{k}r\right).
\end{gather*}
As a result,
\[
N_{k}^{r}<2\left(\gamma_{k}^{r}k^{-1}-2\alpha_{k}r\right)^{-1}\sup_{z\in F}\left\Vert z\right\Vert +1.
\]
This, however, contradicts \eqref{eq:-26}. Thus \eqref{eq:-27-1}
does hold. Next, using the triangle inequality, we see by \eqref{eq:-1-1},
\eqref{eq:-13-1} and \eqref{eq:-29} that
\begin{gather}
\rho_{\mathcal{N}_{\Omega}}\left(T,S\right)\le\rho_{\mathcal{N}_{\Omega}}\left(T,T_{\gamma_{k}^{r}}\right)+\rho_{\mathcal{N}_{\Omega}}\left(T_{\gamma_{k}^{r}},S\right)<\nonumber \\
2\gamma_{k}^{r}\sup_{z\in F}\left\Vert z\right\Vert +\alpha_{k}r<\left(1-\alpha_{k}\right)r+\alpha_{k}r=r.\label{eq:-32-1}
\end{gather}
From \eqref{eq:-27-1} and \eqref{eq:-32-1} it now follows that
\[
B_{\rho_{\mathcal{N}_{\Omega}}}\left(T_{\gamma_{k}^{r}},\alpha_{k}r\right)\subset B_{\rho_{\mathcal{N}_{\Omega}}}\left(T,r\right)\cap\mathcal{F}_{k}=B_{\rho_{\mathcal{N}_{\Omega}}}\left(T,r\right)\backslash\mathcal{G}_{k}.
\]
Hence $\mathcal{G}_{k}$ is indeed a porous subset of $\mathcal{N}_{\Omega}$,
as asserted.
\end{proof}

\section{\label{sec4}Proofs of the main results}

\makeatletter \renewenvironment{proof}[1][\proofname\space of Theorem \ref{Theorem 1}] {\par\pushQED{\qed}\normalfont\topsep6\p@\@plus6\p@\relax\trivlist\item[\hskip\labelsep\bfseries#1\@addpunct{.}]\ignorespaces}{\popQED\endtrivlist\@endpefalse} \makeatother
\begin{proof}
By Lemma \ref{lem1}, there is a sequence of subsets $\left\{ \mathcal{F}_{n}\right\} _{n=1}^{\infty}$
of $\mathcal{M}_{\Omega}$ such that for each positive integer $n$,
the set $\mathcal{G}_{n}:=\mathcal{M}_{\Omega}\backslash\mathcal{F}_{n}$
is a porous subset of $\mathcal{M}_{\Omega}$ and $\mathcal{F}_{n}$
is the set of all sequences $\left\{ T_{n}\right\} _{n=1}^{\infty}\in\mathcal{M}_{\Omega}$
for which there exists a positive integer $N$ such that for each
mapping $s:\left\{ 1,2,\dots\right\} \rightarrow\left\{ 1,2,\dots\right\} $,
we have
\begin{equation}
\left\Vert \widetilde{T_{s\left(N\right)}}\dots\widetilde{T_{s\left(1\right)}}x-\widetilde{T_{s\left(N\right)}}\dots\widetilde{T_{s\left(1\right)}}y\right\Vert <n^{-1}\label{eq:-33}
\end{equation}
for each $x,y\in K$. Set $\mathcal{F}:=\cap_{n=1}^{\infty}\mathcal{F}_{n}$.
Then $\mathcal{M}_{\Omega}\backslash\mathcal{F}=\cup_{n=1}^{\infty}\mathcal{G}_{n}$
is a $\sigma$-porous subset of $\mathcal{M}_{\Omega}$.

Let $\left\{ T_{n}\right\} _{n=1}^{\infty}\in\mathcal{F}$ and let
$\varepsilon>0$. Choose a positive integer $n_{0}$ such that $n_{0}^{-1}<\varepsilon$.
Since $\left\{ T_{n}\right\} _{n=1}^{\infty}\in\mathcal{F}_{n_{0}}$,
we infer from \eqref{eq:-33} that there exists a positive integer
$N$ such that for each integer $n\ge N$ and each mapping $s:\left\{ 1,2,\dots\right\} \rightarrow\left\{ 1,2,\dots\right\} $,
\begin{equation}
\left\Vert \widetilde{T_{s\left(n\right)}}\dots\widetilde{T_{s\left(1\right)}}x-\widetilde{T_{s\left(n\right)}}\dots\widetilde{T_{s\left(1\right)}}y\right\Vert \le\left\Vert \widetilde{T_{s\left(N\right)}}\dots\widetilde{T_{s\left(1\right)}}x-\widetilde{T_{s\left(N\right)}}\dots\widetilde{T_{s\left(1\right)}}y\right\Vert <n_{0}^{-1}<\varepsilon\label{eq:}
\end{equation}
for each $x,y\in K$. This completes the proof.
\end{proof}
\makeatletter \renewenvironment{proof}[1][\proofname\space of Theorem \ref{Theorem 2}] {\par\pushQED{\qed}\normalfont\topsep6\p@\@plus6\p@\relax\trivlist\item[\hskip\labelsep\bfseries#1\@addpunct{.}]\ignorespaces}{\popQED\endtrivlist\@endpefalse} \makeatother
\begin{proof}
By Lemma \ref{lem2}, there is a sequence of subsets $\left\{ \mathcal{F}_{n}\right\} _{n=1}^{\infty}$
of $\mathcal{N}_{\Omega}$ such that for each positive integer $n$,
the set $\mathcal{G}_{n}:=\mathcal{N}_{\Omega}\backslash\mathcal{F}_{n}$
is a porous subset of $\mathcal{N}_{\Omega}$ and $\mathcal{F}_{n}$
is the set of all mappings $T\in\mathcal{N}_{\Omega}$ for which there
exists a positive integer $N$ satisfying
\begin{equation}
\left\Vert \widetilde{T}^{N}x-\widetilde{T}^{N}y\right\Vert <n^{-1}\label{eq:-33-1}
\end{equation}
for each $x,y\in K$. Set $\mathcal{F}:=\cap_{n=1}^{\infty}\mathcal{F}_{n}$.
Then $\mathcal{N}_{\Omega}\backslash\mathcal{F}=\cup_{n=1}^{\infty}\mathcal{G}_{n}$
is a $\sigma$-porous subset of $\mathcal{N}_{\Omega}$.

Let $T\in\mathcal{F}$ and let $\varepsilon>0$ be arbitrary. Choose
a positive integer $n_{0}$ such that $n_{0}^{-1}<\varepsilon$. Since
$T\in\mathcal{F}_{n_{0}}$, we infer from \eqref{eq:-33-1} that there
exists a positive integer $N$ such that for each integer $n\ge N$,
\begin{equation}
\left\Vert \widetilde{T}^{n}x-\widetilde{T}^{n}y\right\Vert <\left\Vert \widetilde{T}^{N}x-\widetilde{T}^{N}y\right\Vert <n_{0}^{-1}<\varepsilon\label{eq:-3}
\end{equation}
for each $x,y\in K$. Clearly, for all integers $n,m\ge N$, we have
\begin{equation}
\left\Vert \widetilde{T}^{n}x-\widetilde{T}^{m}x\right\Vert <\varepsilon\label{eq:-4-1}
\end{equation}
for each $x\in K$. Since $\varepsilon$ is an arbitrary positive
number, inequality \eqref{eq:-4-1} and the completeness of the subspace
$F$ of $\left(X,\left\Vert \cdot\right\Vert \right)$ imply that
the sequence $\left\{ \widetilde{T}^{n}\right\} _{n=1}^{\infty}$
converges to an operator $P:K\rightarrow F$, uniformly on $K$. By
taking the limit in \eqref{eq:-3}, we see that $P$ is constant on
$K$, that is, there exists a point $x_{T}\in K$ such that the sequence
$\left\{ \widetilde{T}^{n}x\right\} _{n=1}^{\infty}\rightarrow x_{T}$
as $n\rightarrow\infty$, uniformly on $K$. Pick an arbitrary point
$x_{0}\in K$. Since the operator $\widetilde{T}$ is continuous,
it follows that
\[
\widetilde{T}x_{T}=\widetilde{T}\lim_{n\rightarrow\infty}\widetilde{T}^{k}x_{0}=\lim_{k\rightarrow\infty}\widetilde{T}^{k+1}x_{0}=x_{T}.
\]
Hence $x_{T}\in K$ is the unique fixed point of the operator $\widetilde{T}$,
as asserted.
\end{proof}
\begin{rem}
We take this opportunity to correct two misprints in \cite{key-4}.
\end{rem}
\begin{itemize}
\item Page 332, second paragraph: The sentence ``Note that this mapping
is onto $K$.'' should be replaced by the sentence ``Note that the
mapping defined on $\mathcal{N}_{\Omega}$ by $T\mapsto\widetilde{T}$
is onto $\mathcal{N}$.''
\item Page 347: The formula
\[
\widetilde{R_{n}}x_{R}=\widetilde{R_{n}}\lim_{k\rightarrow\infty}\widetilde{R_{n}}^{k}x=\lim_{k\rightarrow\infty}\widetilde{R_{n}}^{k+1}x_{R}=x_{R}
\]
should be replaced by the formula
\[
\widetilde{R_{n}}x_{R}=\widetilde{R_{n}}\lim_{k\rightarrow\infty}\widetilde{R_{n}}^{k}x=\lim_{k\rightarrow\infty}\widetilde{R_{n}}^{k+1}x=x_{R}.
\]
\end{itemize}
\begin{acknowledgement*}
Simeon Reich was partially supported by the Israel Science Foundation
(Grant 820/17), the Fund for the Promotion of Research at the Technion
and by the Technion General Research Fund.
All the authors are grateful to the editor and to an anonymous referee for their useful comments and helpful suggestions.     
\end{acknowledgement*}
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\end{document}
